更新 Calculate.py

This commit is contained in:
Mingkun Wang 2023-03-13 15:03:23 +08:00 committed by 965
parent a6689d7352
commit 4dfd1e6b69
6 changed files with 72 additions and 6 deletions

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@ -1,4 +1,4 @@
<?xml version="1.0" encoding="UTF-8"?>
<project version="4">
<component name="ProjectRootManager" version="2" project-jdk-name="Python 3.10 (PythonLearning)" project-jdk-type="Python SDK" />
<component name="ProjectRootManager" version="2" project-jdk-name="Python 3.11 (PythonLearning)" project-jdk-type="Python SDK" />
</project>

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@ -4,7 +4,7 @@
<content url="file://$MODULE_DIR$">
<excludeFolder url="file://$MODULE_DIR$/venv" />
</content>
<orderEntry type="jdk" jdkName="Python 3.10 (PythonLearning)" jdkType="Python SDK" />
<orderEntry type="jdk" jdkName="Python 3.11 (PythonLearning)" jdkType="Python SDK" />
<orderEntry type="sourceFolder" forTests="false" />
</component>
</module>

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@ -4,11 +4,12 @@ In = input()
'''
eval()函数可对括号中的含变量表达式做运算
0 1 2 3 4 5 6 :正向递增序号
" 1 2 3 4 5 "
a b c d e f g
-7 -6 -5 -4 -3 -2 -1 :反向递减序号
使用[]获取字符串中一个或多个字符
str[0]获取第一个字 str[0:2]获取前两个字 str[0:-1]字符串去掉末位后输出 str[1:]去首位
str[0]获取第一个字 str[0:2]获取前两个字 str[0:-1]字符串去掉末位后输出 str[1:]去首位
str[m:n[:k]]m位至n位k为步长
str[::-1]倒置字符串
['F', 'f', ''] : 列表类型数据
'''
numdata = eval(In[0:-1])
@ -34,3 +35,17 @@ elif In[-1] in ['C', 'c', '°C']:
else:
print("Syntax Error")
'''
import math # 引入math库
a = float(input())
b = float(input())
c = float(input())
delta = math.pow(b, 2) - 4 * a * c# 计算判别式
if delta >= 0:
x1 = (-b + math.sqrt(delta)) / (2 * a)
x2 = (-b - math.sqrt(delta)) / (2 * a) #括号很重要!!!!!!!!!
print("X1=", round(x1, 2), " X2=", round(x2, 2))
else:
print("没有实数解")
'''

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@ -83,7 +83,6 @@ for i in range(0, 5):
pendown()
circle(100)
'''
'''
import turtle
@ -103,4 +102,3 @@ y = [-75, -75, -75, -155, -155]
for i in range(5):
circle(x[i], y[i], 360, 100, 15, color[i])
turtle.done()
'''

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@ -0,0 +1,53 @@
# encoding utf-8
import linecache
import re
import os
def opentxt(num, path, name, line):
filename = '.\\{0}\\{1}{2}.txt'.format(path, num, name)
cont = linecache.getline(filename, line)
return cont
def savetxt(num, path, inv, name, character):
filename = '.\\{0}\\{1}{2}.txt'.format(path, num, name)
with open(filename, 'w', encoding='UTF-8') as txt:
txt.write(inv.replace(character, '\n'))
def txtsearch(num, path, character):
filename = '.\\{0}\\{1}_Response.txt'.format(path, num)
txt = open(filename, 'r', encoding='UTF-8')
lines = txt.readlines()
for lines in lines: # 对TXT 进行逐行读取
if character in lines:
return lines
txt.close()
count = 2
while count < 26:
content = txtsearch(count, 'response', 'answer')
texts = re.findall(r'<answers>.*<\\/answers>', content)
texts = str(texts)
texts = re.findall(r'CDATA\[.]', texts)
texts = str(texts)
texts = texts.replace("'CDATA[]]'", '\n')
texts = texts.replace("CDATA", '')
savetxt(count, 'Ans', texts, 'ans', ',')
count += 1
os.chdir(r"C:/Users/965/Builds/iSmartAnsCatch/Ans")
filedir = "C:/Users/965/Builds/iSmartAnsCatch/Ans"
f = open('../Ans.txt', 'w')
# 遍历文件名
for i in range(2, 26):
filename1 = str(i) + 'ans.txt'
if i > 0:
filepath = filedir + '/' + filename1
# 遍历单个文件 读取行数
for line1 in open(filepath, encoding='UTF-8'):
f.writelines(str(i - 1) + line1)
f.write('\n')
f.close()

0
temp.py Normal file
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